S4 Chemistry · Unit 9

Group 14 Elements
and Their Compounds

Carbon allotropes · Silicon chemistry · Oxides and chlorides · +2 vs +4 oxidation states · The inert pair effect · Diagonal relationship B–Si

9.1 Physical Properties 9.2 Carbon Allotropes 9.3 Silicon 9.4 Oxides 9.5 Chlorides 9.6 Oxidation States 9.7 Tin & Lead 9.8 Diagonal Relationship Exercises Quiz Unit Test
9.1

Physical Properties of Group 14 Elements

Overview of Group 14

Group 14 (also called Group IVA or Group IVB) contains Carbon (C), Silicon (Si), Germanium (Ge), Tin (Sn), and Lead (Pb). All have the outer electron configuration ns²np² giving 4 valence electrons.

This group shows the most dramatic transition from non-metal to metal of any group — carbon is a non-metal, silicon and germanium are metalloids (semiconductors), while tin and lead are true metals.

ElementSymbolZElectron ConfigM.p. (°C)CharacterCommon OS
CarbonC6[He]2s²2p²3550 (diamond)Non-metal−4, 0, +2, +4
SiliconSi14[Ne]3s²3p²1414Metalloid / semiconductor+4, −4
GermaniumGe32[Ar]3d¹⁰4s²4p²938Metalloid / semiconductor+4, +2
TinSn50[Kr]4d¹⁰5s²5p²232Metal (soft, silvery)+2, +4
LeadPb82[Xe]4f¹⁴5d¹⁰6s²6p²327Soft, dense metal+2 (stable), +4

Trends Down Group 14

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Why does Group 14 span all three classes? Carbon at the top is a typical non-metal — small atomic radius, high electronegativity, forms covalent bonds. Silicon and Germanium have intermediate properties (semiconductors used in electronics). Tin and Lead at the bottom have metallic structures with delocalised electrons — they conduct electricity and are malleable.
9.2

Carbon and Its Allotropes

Definition — Allotropy The existence of an element in two or more different physical forms in the same physical state, with different arrangements of atoms. Each form is called an allotrope.

Diamond

In diamond, each carbon atom is sp³ hybridised and bonded to four other carbon atoms in a regular tetrahedral arrangement, forming a giant covalent (macromolecular) structure. Bond angle = 109.5°.

C C C C C 109.5° sp³ hybridised tetrahedral Giant covalent lattice
DIAMOND: Each C bonded to 4 others — tetrahedral giant covalent structure

Properties of Diamond:

Graphite

In graphite, each carbon atom is sp² hybridised and bonded to three other carbon atoms in a flat hexagonal layer. Bond angle = 120°. The unhybridised p orbital on each carbon overlaps sideways to form a delocalised π system extending across each layer.

van der Waals forces delocalised π electrons → conducts Layers slide (lubricant)
GRAPHITE: Layered hexagonal structure. Layers held by weak van der Waals forces

Properties of Graphite:

Fullerenes (C₆₀ — Buckminsterfullerene)

Discovered in 1985. C₆₀ consists of 60 carbon atoms arranged in 12 pentagons and 20 hexagons — resembling a football (soccer ball). Each carbon is sp² hybridised and bonded to 3 others. The molecule is approximately spherical with diameter ~0.7 nm.

Properties: Molecular solid (not giant covalent) — held together by van der Waals forces → low melting point. Poor conductor as a solid but can be doped to become superconducting. Used in nanotechnology, drug delivery research, and as lubricants.

Carbon nanotubes are a related form — sheets of graphene (single graphite layer) rolled into cylinders. Extremely high tensile strength (~100× steel). Conduct electricity along the tube axis.

Graphene

A single layer of graphite — one atom thick. It is the thinnest and one of the strongest materials known. Graphene conducts electricity and heat exceptionally well and is transparent (~97.7% of visible light passes through). It is considered a 2D material.

AllotropeStructureHybridisationBonds/CConductivityMelting PointKey Use
DiamondGiant covalent 3Dsp³4None~3550°CCutting tools, jewellery
GraphiteLayered hexagonalsp²3 (+ π)Good (along layers)~3600°C (sublime)Electrodes, pencils, lubricants
C₆₀ (Fullerene)Molecular spheressp²3Poor (undoped)~600°C (sublimes)Nanotechnology, research
GrapheneSingle hexagonal layersp²3 (+ π)Excellent~3600°CElectronics, composites
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Memory tip — Diamond vs Graphite conductivity Diamond — all 4 electrons bonding → no free electrons → non-conductor. Graphite — only 3 electrons bonding → 1 free per carbon in π system → conducts. "DiamonDs Don't conduct, Graphite Goes electricity."
9.3

Silicon Chemistry

Structure and Properties of Silicon

Silicon has the same giant covalent structure as diamond — each Si is sp³ hybridised and bonded to 4 other Si atoms tetrahedrally. However, Si–Si bonds are weaker than C–C bonds (Si is larger, bonds are longer → lower bond energy).

Properties of Silicon:

Silicon Dioxide (Silica, SiO₂)

SiO₂ has a giant covalent structure — each Si is bonded to 4 oxygen atoms (tetrahedral), and each O bridges two Si atoms. There are NO discrete SiO₂ molecules. The formula SiO₂ is an empirical formula representing the ratio Si:O = 1:2.

Compare: CO₂ is a simple molecular compound (small discrete molecules, low m.p.). SiO₂ is a giant covalent compound (no discrete molecules, very high m.p. ~1713°C).

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Why doesn't SiO₂ have a structure like CO₂? Carbon can form strong C=O double bonds (pπ–pπ overlap is effective for small atoms). Silicon is larger — Si=O double bonds are weak (poor pπ–pπ overlap between 3p orbitals). Si prefers to form 4 Si–O single bonds in a 3D network rather than 2 Si=O double bonds.

Reactions of SiO₂:

SiO₂ + 2NaOH → Na₂SiO₃ + H₂O (acidic oxide reacts with base) SiO₂ + CaO → CaSiO₃ (used in glassmaking / cement) SiO₂ + 4HF → SiF₄ + 2H₂O (only common acid to attack silica)

SiO₂ is an acidic oxide. It does NOT react with water (insoluble) or with most acids except HF.

Silicates

Silicates contain the fundamental unit SiO₄⁴⁻ (a tetrahedron). These tetrahedra can link in various ways — single units, chains, rings, sheets, and 3D networks — giving the huge variety of silicate minerals (quartz, feldspar, mica, clay). Na₂SiO₃ (sodium silicate) is soluble in water — used in detergents and as "water glass."

9.4

Oxides of Group 14 Elements

Element+4 OxideStructureAcid/Base?+2 OxideAcid/Base?
Carbon (C)CO₂Simple molecular (O=C=O)AcidicCONeutral
Silicon (Si)SiO₂Giant covalentAcidicSiO (rare)
Germanium (Ge)GeO₂SolidAmphotericGeOBasic
Tin (Sn)SnO₂SolidAmphotericSnOBasic
Lead (Pb)PbO₂SolidAmphotericPbOBasic/amphoteric

Carbon Oxides in Detail

Carbon dioxide (CO₂): Linear molecule (O=C=O). Carbon is sp hybridised. Acidic oxide:

CO₂ + H₂O ⇌ H₂CO₃ (carbonic acid — weak, Ka₁ = 4.3×10⁻⁷) CO₂ + 2NaOH → Na₂CO₃ + H₂O (excess NaOH) CO₂ + NaOH → NaHCO₃ (excess CO₂) CO₂ + CaO → CaCO₃ (important in cement)

Carbon monoxide (CO): Colourless, odourless, extremely toxic gas. CO binds to haemoglobin 200× more strongly than O₂ → prevents O₂ transport → tissue death. CO is a neutral oxide — does not react with water. It is a strong reducing agent:

CO + ½O₂ → CO₂ (combustion) Fe₂O₃ + 3CO → 2Fe + 3CO₂ (blast furnace — reduction of iron ore) CO + 2H₂ ⇌ CH₃OH (methanol synthesis)

CO has a dative (coordinate) bond structure: :C≡O: — one of the bonds is dative from O to C. CO is isoelectronic with N₂.

Lead Oxides

Lead forms several oxides: PbO (litharge, yellow), PbO₂ (brown), and Pb₃O₄ (red lead, minium — a mixed oxide containing Pb²⁺ and Pb⁴⁺). PbO is predominantly basic, but also shows slight amphoteric character. PbO₂ is a strong oxidising agent used in lead-acid batteries.

9.5

Chlorides of Group 14 Elements

ChlorideTypeState (room T)Reaction with WaterNotes
CCl₄Simple covalentLiquidDoes NOT hydrolyse — no reactionNo d orbitals on C to accept lone pair; too small for nucleophilic attack
SiCl₄Simple covalentLiquidVigorous hydrolysis — fumes of HClSi has empty 3d orbitals — can expand octet; attacks by H₂O
GeCl₄CovalentLiquidHydrolysisSimilar to SiCl₄
SnCl₂Ionic (Sn²⁺)SolidPartial hydrolysis → Sn(OH)Cl↓Reducing agent; dissolves in HCl
SnCl₄CovalentLiquidHydrolysis
PbCl₂Ionic (Pb²⁺)Solid (white)Sparingly soluble — slightly soluble in hot waterPrecipitate test for Pb²⁺
PbCl₄CovalentYellow oily liquidHydrolysisUnstable — decomposes to PbCl₂ + Cl₂

CCl₄ vs SiCl₄ — Key Comparison

This is one of the most important comparisons in A-Level Group 14:

CCl₄ + H₂O → NO REACTION SiCl₄ + 2H₂O → SiO₂ + 4HCl (overall — via Si(OH)₄) SiCl₄ + 4H₂O → Si(OH)₄ + 4HCl (stepwise hydrolysis)
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Why does SiCl₄ hydrolyse but CCl₄ does not? Carbon in CCl₄ has no empty low-energy orbitals available (2p are full, 3d are too high in energy) — water cannot donate its lone pair to C. Silicon in SiCl₄ has empty 3d orbitals at accessible energy — a lone pair from H₂O's oxygen attacks Si, forming a 5-coordinate intermediate → bond breaks → HCl released. This is a nucleophilic substitution (addition-elimination) mechanism.
Worked Example 9.1 — Identifying the Products

Question: SiCl₄ is added to excess water. Write the equation and explain what is observed.

1

SiCl₄ reacts vigorously with water. The Cl⁻ is displaced and HCl is produced.

2

SiCl₄ + 2H₂O → SiO₂ + 4HCl

3

Observations: White fumes (HCl gas) produced. White solid or gel (SiO₂ / silicic acid Si(OH)₄) forms. The reaction is exothermic.

4

Contrast: CCl₄ added to water — no visible reaction (CCl₄ is denser than water, sinks to the bottom, no fumes).

9.6

+2 and +4 Oxidation States — The Inert Pair Effect

The Inert Pair Effect

Going down Group 14 (and Groups 13, 15), the +2 oxidation state becomes increasingly stable relative to +4. This is called the inert pair effect.

Explanation: The outermost s electrons (ns²) are called the "inert pair." For heavier elements (Sn, Pb), the ns² electrons are in an orbital that has penetrated through many inner electron shells and the relativistic effects increase. The energy required to unpair and use these 2s electrons for bonding is not recovered by the additional bond energies formed. As a result:

Stability of +2 vs +4 Oxidation State Down Group 14 C Si Ge Sn Pb +4✓ +4✓ +4✓ +4✓ +2✓ +2✓ +2 dominant +2 increasingly stable ↓; +4 less stable ↓
Inert pair effect: +4 dominant at top, +2 dominant at bottom of group
Worked Example 9.2 — Inert Pair Effect in Practice

Question: Explain why PbCl₄ is a stronger oxidising agent than SnCl₄.

1

PbCl₄ contains Pb in the +4 oxidation state. Due to the inert pair effect, Pb(+4) is unstable relative to Pb(+2) — it has a strong tendency to be reduced to Pb²⁺.

2

PbCl₄ → PbCl₂ + Cl₂ (easily — releases Cl₂ even at room temperature)

3

Sn(+4) in SnCl₄ is much more stable — the inert pair effect is less pronounced for Sn than for Pb. SnCl₄ does not readily release Cl₂.

4

Conclusion: PbCl₄ more readily accepts electrons (is reduced) → stronger oxidising agent.

9.7

Tin and Lead — Reactions and Compounds

Reactions of Tin and Lead with Acids and Alkalis

Tin + dilute HCl: Sn + 2HCl → SnCl₂ + H₂↑ Tin + hot conc. HNO₃: Sn + 4HNO₃(conc.) → SnO₂ + 4NO₂ + 2H₂O Tin + NaOH(aq): Sn + 2NaOH + 2H₂O → Na₂[Sn(OH)₄] + H₂↑ (tetrahydroxostannate(II) — amphoteric behaviour) Lead + dilute HCl: Pb + 2HCl → PbCl₂↓ + H₂↑ (slow — PbCl₂ insoluble, coats surface) Lead + dilute HNO₃: 3Pb + 8HNO₃(dil.) → 3Pb(NO₃)₂ + 2NO↑ + 4H₂O Lead + NaOH(aq): Pb + 2NaOH + 2H₂O → Na₂[Pb(OH)₄] + H₂↑

Identification of Sn²⁺ and Pb²⁺ Ions

IonTest ReagentObservationEquation
Sn²⁺NaOH(aq)White ppt of Sn(OH)₂; dissolves in excess NaOH (amphoteric)Sn²⁺ + 2OH⁻ → Sn(OH)₂↓; Sn(OH)₂ + 2OH⁻ → [Sn(OH)₄]²⁻
Pb²⁺NaOH(aq)White ppt of Pb(OH)₂; dissolves in excess NaOHPb²⁺ + 2OH⁻ → Pb(OH)₂↓; Pb(OH)₂ + 2OH⁻ → [Pb(OH)₄]²⁻
Pb²⁺KI(aq)Bright yellow ppt of PbI₂Pb²⁺ + 2I⁻ → PbI₂↓ (yellow)
Pb²⁺H₂SO₄(aq)White ppt of PbSO₄Pb²⁺ + SO₄²⁻ → PbSO₄↓ (white)
Pb²⁺Cl⁻ (HCl)White ppt PbCl₂; dissolves in hot waterPb²⁺ + 2Cl⁻ → PbCl₂↓

Tin as a Reducing Agent (SnCl₂)

Sn²⁺ is easily oxidised to Sn⁴⁺ — making SnCl₂ a useful reducing agent in the laboratory:

SnCl₂ + 2FeCl₃ → SnCl₄ + 2FeCl₂ (Sn²⁺ reduces Fe³⁺ → Fe²⁺) SnCl₂ + 2HgCl₂ → SnCl₄ + Hg₂Cl₂↓ (test for Hg²⁺)
9.8

Diagonal Relationship: Boron and Silicon

What is the Diagonal Relationship?

Elements in the second row of the periodic table (Period 2) often show similarities with the element to the lower right (diagonal) in Period 3. This happens because charge density (charge/radius) is similar diagonally.

The most important diagonal relationships are: Li–Mg, Be–Al, and B–Si.

Similarities Between Boron (B) and Silicon (Si)

PropertyBoron (B)Silicon (Si)
Electronegativity2.01.8 (similar)
Structure of elementGiant covalentGiant covalent
Oxide typeB₂O₃ — acidicSiO₂ — acidic
Oxide structureGiant covalent / glass-likeGiant covalent
Chloride hydrolysisBCl₃ + 3H₂O → B(OH)₃ + 3HClSiCl₄ + 4H₂O → Si(OH)₄ + 4HCl
HydridesB₂H₆ (diborane) — electron deficientSiH₄ (silane) — forms covalent hydrides
Nature of halidesCovalent, hydrolyse in waterCovalent, hydrolyse in water
Forms glassy oxidesB₂O₃ — borosilicate glass componentSiO₂ — major glass component
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Why B and Si (not B and Al or B and C)? Moving one period down increases the atomic radius and decreases charge density. Moving one group to the right increases the nuclear charge which also affects charge density. These two effects partially cancel each other diagonally — the result is that B (Group 13, Period 2) and Si (Group 14, Period 3) have similar charge densities (~2.7 vs ~2.6 C pm⁻²) and thus similar chemical behaviour.

Uses of Group 14 Elements and Compounds

SubstanceUseReason
DiamondCutting, drilling, polishing tools; jewelleryHardest natural substance; gemstone
GraphitePencil "lead"; electrodes; lubricant; nuclear moderatorSoft layered structure; conducts; high m.p.
SiliconSemiconductors, transistors, solar cells, microchipsSemiconductor — band gap can be engineered by doping
SiO₂Glass, optical fibres, silica gel (desiccant)Transparent, thermally stable, inert
SiliconesWaterproofing, lubricants, sealants, breast implantsChemically inert, flexible polymer backbone (Si–O–Si)
SnO₂Transparent conducting layer in LCDs; ceramic glazesConducts while transparent when doped
Pb in PbO₂Lead-acid car batteries (cathode)Strong oxidising agent, reversible electrode reactions
Sn (tinplate)Food cans — tin coating on steelCorrosion resistant, non-toxic

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Exercises

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Multiple Choice Quiz — 25 Questions

Unit 9: Group 14 Elements and Compounds

25 Questions · Select one answer each
Q1

What is the outer electron configuration of all Group 14 elements?

All Group 14 elements have ns²np² (4 valence electrons). This gives 4 available bonding electrons — the key to the +4 oxidation state.
Q2

Which allotrope of carbon has a giant covalent structure and does NOT conduct electricity?

Diamond is a giant covalent structure where all 4 valence electrons are used in C–C bonds → no free electrons → non-conductor. Graphite, graphene, and C₆₀ all have sp² carbon with delocalised π electrons.
Q3

Why does graphite conduct electricity but diamond does not?

In graphite: sp² C uses 3 electrons for σ bonds → 1 electron per C enters the delocalised π system → free to carry charge. Diamond: sp³ C uses all 4 electrons in σ bonds → no free electrons.
Q4

The lubricating property of graphite is due to:

The layers in graphite are held by weak London dispersion (van der Waals) forces → layers can slide easily over each other → graphite is soft and a good lubricant. The strong C–C covalent bonds within each layer are irrelevant to lubrication.
Q5

Which statement correctly describes the structure of SiO₂?

SiO₂ is a giant covalent (macromolecular) network solid. SiO₂ is the empirical formula. Each Si is sp³-bonded to 4 oxygens; each O bridges 2 Si atoms. No discrete molecules exist. Contrast with CO₂ (simple molecular, O=C=O).
Q6

SiCl₄ is rapidly hydrolysed by water but CCl₄ is not. What is the main reason?

The key: Si has empty 3d orbitals (energetically accessible) that water's oxygen lone pair can attack → forms 5-coordinate intermediate → Cl⁻ displaced → hydrolysis proceeds. Carbon has no empty low-energy orbitals → H₂O cannot attack → CCl₄ unreactive towards water.
Q7

What are the products when SiCl₄ reacts with excess water?

SiCl₄ + 2H₂O → SiO₂ + 4HCl. The intermediate is Si(OH)₄ (silicic acid) which dehydrates to SiO₂. White solid/gel forms and white fumes of HCl are observed.
Q8

The inert pair effect explains why, going down Group 14:

The inert pair effect: the ns² electrons become harder to use in bonding in heavier elements. The energy cost of unpairing the s² electrons is not recovered by the extra bond energies formed at the +4 state. Thus the +2 state (ns² left as lone pair) becomes increasingly stable going down: C,Si → +4 dominant; Sn → both; Pb → +2 dominant.
Q9

Which of the following is the most stable oxidation state for lead in aqueous solution?

Due to the inert pair effect, Pb(+2) is the dominant stable state in aqueous solution. The 6s² electron pair in lead is "inert" — too stable to be used in bonding. Pb(+4) compounds are strong oxidising agents that readily revert to Pb(+2).
Q10

Carbon monoxide (CO) is toxic because:

CO binds to the Fe²⁺ centre in haemoglobin approximately 200 times more strongly than O₂ (carboxyhaemoglobin is very stable). This prevents O₂ from being carried to tissues → oxygen deprivation → tissue death. Treatment: high-flow O₂ or hyperbaric O₂ to displace CO.
Q11

What is the oxidation state of carbon in CO?

In CO: C + O = 0. O has OS = −2 (more electronegative). Therefore C = +2. Note: CO is a neutral oxide — it does not react with water. Compare CO₂: C = +4.
Q12

Which Group 14 element is used as a semiconductor in computer chips?

Silicon is the dominant semiconductor material. It has a suitable band gap (~1.1 eV) that can be modified by controlled doping with Group 13 (p-type) or Group 15 (n-type) elements. "Silicon Valley" is named after silicon's dominance in microelectronics.
Q13

The reaction Fe₂O₃ + 3CO → 2Fe + 3CO₂ occurs in the blast furnace. In this reaction, CO acts as:

CO is oxidised from +2 (in CO) to +4 (in CO₂) — it loses electron density → CO is the REDUCING agent. Fe₂O₃ gains electrons (Fe³⁺ → Fe⁰) — Fe₂O₃ is the oxidising agent. "CO removes oxygen from iron oxide" = CO reduces Fe₂O₃.
Q14

Which allotrope of carbon has a simple molecular structure?

C₆₀ (Buckminsterfullerene) consists of discrete C₆₀ molecules held together by weak van der Waals forces — it is a simple molecular solid. Diamond and graphite are both giant covalent structures (macromolecular).
Q15

SiO₂ reacts with molten sodium oxide (Na₂O) to give:

SiO₂ + Na₂O → Na₂SiO₃. SiO₂ is an acidic oxide — it reacts with basic oxides to form silicates. Na₂SiO₃ (sodium silicate / "water glass") is soluble in water and used in detergents, adhesives, and as a fire retardant.
Q16

A white precipitate forms when HCl(aq) is added to Pb(NO₃)₂(aq). The precipitate is:

Pb²⁺ + 2Cl⁻ → PbCl₂↓ (white precipitate). PbCl₂ is sparingly soluble in cold water but dissolves in hot water. This is used as a qualitative test for Pb²⁺ ions. Note: PbCl₄ is unstable and does not form under these conditions.
Q17

Which of the following correctly states the hybridisation and bond angle in diamond?

Diamond: each carbon is sp³ hybridised (4 equivalent C–C single bonds) with tetrahedral geometry → bond angle = 109.5°. Graphite: sp² hybridised, 120°. No carbon allotrope uses sp hybridisation.
Q18

The diagonal relationship exists between B and Si because they have similar:

The diagonal relationship arises because moving one period down increases atomic radius (decreasing charge density) while moving one group right increases nuclear charge (increasing charge density). These effects partially cancel → B (Period 2, Group 13) and Si (Period 3, Group 14) have similar charge densities → similar chemistry.
Q19

Which property of graphite makes it suitable for use as an electrode?

Graphite electrodes: (1) Conducts electricity — delocalised π electrons carry current. (2) Very high melting point (~3600°C) — stable at high temperatures in electrolysis/furnaces. (3) Chemically inert to most electrolytes. (4) Relatively cheap and easy to machine.
Q20

SnCl₂ acts as a reducing agent in many reactions. What happens to tin during reduction by SnCl₂?

When SnCl₂ acts as a reducing agent, it reduces something else — meaning Sn itself is oxidised. Sn²⁺ → Sn⁴⁺ + 2e⁻ (Sn is oxidised, losing 2 electrons). SnCl₂ + 2FeCl₃ → SnCl₄ + 2FeCl₂. Sn²⁺ is oxidised to Sn⁴⁺; Fe³⁺ is reduced to Fe²⁺.
Q21

What is observed when NaOH(aq) is added to Pb²⁺(aq) first in small amounts and then in excess?

Pb²⁺ + 2OH⁻ → Pb(OH)₂↓ (white ppt). Pb(OH)₂ is amphoteric. In excess NaOH: Pb(OH)₂ + 2OH⁻ → [Pb(OH)₄]²⁻ (soluble tetrahydroxoplumbate(II)). This distinguishes Pb²⁺ from Ca²⁺ and Mg²⁺ (whose hydroxides do not dissolve in excess NaOH).
Q22

Which acid reacts with SiO₂ (silica)?

SiO₂ + 4HF → SiF₄ + 2H₂O. HF is the only common acid that attacks silica. Si–F bonds are very strong (thermodynamic driving force). This is why HF is stored in plastic bottles (not glass — it would dissolve the glass). All other listed acids do not react with SiO₂.
Q23

Carbon dioxide (CO₂) has a much lower melting point than silicon dioxide (SiO₂) because:

CO₂: discrete O=C=O molecules held by weak London dispersion forces → melts/sublimes at −78.5°C. SiO₂: giant 3D covalent network where every Si–O bond must be broken → m.p. ~1713°C. The difference in structure (molecular vs giant covalent) explains the enormous difference in m.p.
Q24

PbCl₄ decomposes readily at room temperature. The products are:

PbCl₄ → PbCl₂ + Cl₂. This reflects the inert pair effect: Pb(+4) is unstable and readily reverts to Pb(+2) by releasing Cl₂. PbCl₄ is a strong oxidising agent precisely because of this tendency. Cl₂ (yellow-green gas) is produced.
Q25

Which statement about carbon monoxide (CO) is correct?

CO is a NEUTRAL oxide (does not react with water, neither acidic nor basic). It is a strong reducing agent (reduces metal oxides in blast furnaces, reduces Ag⁺ etc.). CO structure: :C≡O: — a triple bond (one dative bond from O to C). Isoelectronic with N₂. Not to be confused with CO₂ (acidic oxide, forms H₂CO₃ with water).
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Unit Test — 50 Marks

Section A — Short Answer

30 marks
Q1 [4 marks]

Compare the structures of diamond and graphite. For each: state the hybridisation, number of bonds per carbon, type of structure, and whether it conducts electricity. [4]

Diamond: sp³ hybridised; 4 C–C bonds per carbon; giant 3D covalent network; does NOT conduct (all electrons in bonds, no free carriers). [2] Graphite: sp² hybridised; 3 C–C bonds per carbon (+ 1 electron in π system); giant layered covalent structure; DOES conduct along layers (delocalised π electrons free to move). [2]
Q2 [4 marks]

Explain, with reference to orbital theory, why SiCl₄ is hydrolysed by water but CCl₄ is not. Write an equation for the reaction of SiCl₄ with water. [4]

CCl₄: carbon's 2p orbitals are fully occupied; 3d orbitals are too high in energy to participate. Water cannot donate a lone pair to carbon → no reaction. [1] SiCl₄: silicon has empty, accessible 3d orbitals. Water's oxygen donates a lone pair to Si → forms a 5-coordinate intermediate → Cl⁻ is displaced as HCl → hydrolysis continues stepwise. [2] Equation: SiCl₄ + 2H₂O → SiO₂ + 4HCl. White solid/gel (SiO₂) forms and white fumes (HCl) observed. [1]
Q3 [5 marks]

Describe the inert pair effect. Use it to explain the trend in stability of the +2 oxidation state from carbon to lead. Give one specific example for tin and one for lead. [5]

Inert pair effect: the ns² electrons in heavy elements become increasingly stable and are less available for bonding. [1] The energy released by forming two additional bonds (to reach +4) does not compensate the energy required to unpair the s electrons in heavier elements. [1] Trend: C, Si → only +4 stable; Ge → +4 dominant, +2 possible; Sn → both +2 and +4 stable; Pb → +2 dominant. [1] Tin example: SnCl₂ (Sn²⁺) is a stable, common compound; Sn²⁺ acts as a reducing agent. [1] Lead example: PbCl₄ (Pb⁴⁺) is unstable and readily decomposes: PbCl₄ → PbCl₂ + Cl₂. Pb²⁺ is the dominant aqueous ion. [1]
Q4 [4 marks]

Carbon monoxide and carbon dioxide are both oxides of carbon. For each: (a) state the oxidation state of carbon (b) classify the oxide as acidic, basic, or neutral. Write a relevant equation for each classification. [4]

CO: OS of C = +2; neutral oxide — does not react with water or bases. CO + ½O₂ → CO₂ (burns but does not form an acid/base with water). [2] CO₂: OS of C = +4; acidic oxide. Equation: CO₂ + 2NaOH → Na₂CO₃ + H₂O, or CO₂ + H₂O ⇌ H₂CO₃. [2]
Q5 [4 marks]

Describe three similarities in chemistry between boron and silicon that illustrate the diagonal relationship. For each similarity, write a relevant equation. [4] (1 mark for each similarity + equation, 1 mark for explaining the cause)

Cause: B and Si have similar charge densities (charge/radius) because moving one period down and one group right partially cancel → similar chemistry. [1] (1) Both have acidic oxides — giant covalent structures: B₂O₃ + 6NaOH → 2Na₃BO₃ + 3H₂O; SiO₂ + 2NaOH → Na₂SiO₃ + H₂O. (2) Both chlorides are covalent and hydrolyse in water: BCl₃ + 3H₂O → B(OH)₃ + 3HCl; SiCl₄ + 2H₂O → SiO₂ + 4HCl. (3) Both elements form giant covalent structures (extremely high m.p.); B forms complex borides, Si forms silicates — both form polymeric anionic structures. [3, one mark each]
Q6 [5 marks]

Identify the precipitate formed in each reaction involving Pb²⁺ ions: (a) Pb²⁺ + NaOH(aq) [small amount] (b) result of (a) + excess NaOH (c) Pb²⁺ + KI(aq) (d) Pb²⁺ + H₂SO₄(aq) (e) Pb²⁺ + HCl(aq), then warm. State the colour and write an equation for each. [5]

(a) White ppt: Pb²⁺ + 2OH⁻ → Pb(OH)₂↓ (white). (b) Ppt dissolves (clear): Pb(OH)₂ + 2OH⁻ → [Pb(OH)₄]²⁻ (amphoteric). (c) Bright yellow ppt: Pb²⁺ + 2I⁻ → PbI₂↓ (yellow). (d) White ppt: Pb²⁺ + SO₄²⁻ → PbSO₄↓ (white, insoluble in hot water — unlike BaSO₄ and SrSO₄ tests). (e) White ppt forms: Pb²⁺ + 2Cl⁻ → PbCl₂↓; on warming, ppt dissolves (PbCl₂ soluble in hot water). [1 mark each]
Q7 [4 marks]

Draw and describe the structure of C₆₀ (Buckminsterfullerene). Compare its physical properties to diamond and graphite, explaining the differences. [4]

C₆₀: discrete spherical molecule of 60 sp²-hybridised C atoms arranged in 12 pentagons and 20 hexagons (like a football). Diameter ~0.7 nm. Solid C₆₀ held by weak van der Waals forces between molecules. [2] Comparison: Diamond and graphite are giant covalent → very high m.p. (requires breaking many strong covalent bonds). C₆₀ is simple molecular → relatively low m.p. (~600°C sublimation) because only weak van der Waals forces between molecules need to be overcome. Diamond and graphite are insoluble in most solvents; C₆₀ is slightly soluble in non-polar solvents (toluene). Neither diamond nor C₆₀ conducts (undoped); graphite conducts. [2]

Section B — Extended Answer

20 marks
Q8 [10 marks]

(a) Compare the physical and chemical properties of SiO₂ and CO₂. Use your knowledge of structure and bonding to explain the differences. [6]
(b) Write equations for three reactions of SiO₂ and three reactions of CO₂. [4]

(a) Physical: CO₂ is a gas at room temperature (m.p. −78.5°C); SiO₂ is a hard solid (m.p. ~1713°C). CO₂ has simple molecular structure (discrete O=C=O, weak van der Waals) → low m.p./b.p. SiO₂ is a giant covalent network (each Si bonded to 4 O, each O bridges 2 Si, Si–O bonds throughout) → very high m.p. This difference arises because C can form strong C=O double bonds (small atoms, effective p–p π overlap), while Si cannot effectively form Si=O double bonds (larger Si, weaker 3p–2p π overlap) → Si forms 4 single bonds in a network instead. [4] Chemical: CO₂ is an acidic oxide that reacts with water, forming H₂CO₃, and reacts readily with bases. SiO₂ is also an acidic oxide but does NOT react with water or dilute acids (except HF). Both react with strong bases/basic oxides. SiO₂ is thermally stable; CO₂ can be reduced to CO at high temperatures. [2] (b) SiO₂ equations (any 3): SiO₂ + 2NaOH → Na₂SiO₃ + H₂O; SiO₂ + CaO → CaSiO₃; SiO₂ + 4HF → SiF₄ + 2H₂O; SiO₂ + Na₂CO₃ → Na₂SiO₃ + CO₂ (molten). CO₂ equations (any 3): CO₂ + H₂O ⇌ H₂CO₃; CO₂ + 2NaOH → Na₂CO₃ + H₂O; CO₂ + NaOH → NaHCO₃; CO₂ + CaO → CaCO₃; CO₂ + C → 2CO (at high T). [4]
Q9 [10 marks]

(a) Describe the trend in metallic character across Group 14. Relate this to the changes in atomic structure going from carbon to lead. [4]
(b) Explain the chemistry of tin and lead with respect to their oxidation states. Why is SnCl₂ a reducing agent and PbO₂ an oxidising agent? [3]
(c) Silicon is described as a semiconductor. Explain what this means, how it differs from conductors and insulators, and why it is used in solar cells. [3]

(a) Metallic character increases from C (non-metal, high EN, giant covalent/molecular allotropes) → Si (metalloid, semiconductor, EN 1.8) → Ge (metalloid/semiconductor) → Sn (true metal, conducts, malleable) → Pb (soft, heavy metal, conducts). Structural changes: increasing atomic radius (more shells), decreasing ionisation energy, increasing tendency to form metallic bonding (delocalised electrons), decreasing electronegativity. Sn and Pb both form metallic lattices at room temperature. [4] (b) SnCl₂: Sn is in +2 state. Sn²⁺ has a strong tendency to be oxidised to Sn⁴⁺ (the +4 state is still accessible for Sn). When Sn²⁺ is oxidised, it reduces another species (e.g. Fe³⁺ → Fe²⁺). SnCl₂ + 2FeCl₃ → SnCl₄ + 2FeCl₂. PbO₂: Pb is in the +4 state. Due to the inert pair effect, Pb(+4) strongly tends to be reduced to Pb(+2). This means PbO₂ readily accepts electrons → strong oxidising agent. PbO₂ is used as the positive electrode in lead-acid batteries: PbO₂ + 4H⁺ + SO₄²⁻ + 2e⁻ → PbSO₄ + 2H₂O. [3] (c) Semiconductor: conductivity between metals and insulators. Band gap (energy gap between filled valence band and empty conduction band) is small (~1.1 eV for Si) — at 0 K, Si is an insulator; at room temperature, thermal energy promotes electrons across the gap into the conduction band → conducts weakly. Conductors: no band gap (bands overlap). Insulators: very large band gap (>5 eV, e.g. diamond). Solar cells: photons with energy ≥ band gap excite electrons from valence to conduction band → electrical current flows. Si band gap (~1.1 eV) matches well with the solar spectrum energy → efficient light absorption → electrical energy generated. [3]
← Unit 8: Group 13 S4 Course Home Unit 10: Group 15 →

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